AMDG Daya S. Prasad wrote:

Can any body please tell me why operator[] is defined in case of shared_array<T> like this way:

Type & operator[](std::ptrdiff_t) const;

It reports compile time error. Consider the code:

class Widget { std::string classId; public: std::string getClassId() const { return classId; } };

int main() { boost::shared_array<Widget> obj(new Widget[10]); std::string id = obj[7].getClassId (); // Error }

? It compiles fine for me.

In my opinion operator function should be defined as follows:

const Type & operator[](std::ptrdiff_t) const; Type & operator[](std::ptrdiff_t) ;

shared_array is defined like a pointer. int* const array = new int[5]; int& i = array[2]; similarly const boost::shared_array<int> array(new int[5]); int& i = array[2]; In Christ, Steven Watanabe