I don't know about the whole boost::noncopyable, but if you dont want to pass a copy of the class, doesn't a reference/pointer do th trick? On Sat, Sep 26, 2009 at 7:36 AM, Germán Diago wrote:

Hello. The question is simple, but reading the documentation I cannot understand how to do this:

class MyClass : boost::noncopyable {    void f(MyClass2 * c2); };

MyClass2 is not copyable either. So I want to be able to wrap that function, but avoid the copying of MyClass2 when called from python. I want to pass the c++ object directly, not a copy of it.

I'm not sure if this can be done with ptr() or some kind of call policy, but I don't understand the documentation 100%. Any help will be appreciated. Thanks. _______________________________________________ Boost-users mailing list Boost-users@lists.boost.org http://lists.boost.org/mailman/listinfo.cgi/boost-users