Can I return std::unique_ptr in a boost::future?

15 Nov 2013

      I'm trying to return a std::unique_ptr in a boost::future. I can't get it 
to compile. Is it possible? The code wraps a packaged_task in a functor to 
make it copyable enough to pass to a boost::asio::io_service, where the 
work will be done in another thread. The code works for other return types 
that are copyable.

This is what I have for a small test case:

std::unique_ptr< int > get_int_impl(int i)
{
   return std::unique_ptr< int >(new int(i));
}

std::unique_ptr< int > get_int(int i)
{
   typedef boost::packaged_task< std::unique_ptr< int > > Task;

   boost::shared_ptr< Task > task = boost::make_shared< Task
...
(boost::bind(&get_int_impl, 42));
boost::unique_future< std::unique_ptr< int > > future = 
task->get_future(); // <--- Error from this line.

   m_service.post(boost::bind(&Task::operator(), task));

   return future.get();
}

BOOST_AUTO_TEST_CASE(test_get_int)
{
   BOOST_CHECK_EQUAL(*get_int(42), 42);
}

The error:

boost/thread/future.hpp(239): error C2248: 
'std::unique_ptr<_Ty>::unique_ptr' : cannot access private member declared 
in class 'std::unique_ptr<_Ty>'
---

Aaron Wright

Aaron_Wright＠selinc.com

Klaim - Joël Lamotte

Vicente J. Botet Escriba

Gavin Lambert

Aaron_Wright＠selinc.com

Aaron_Wright＠selinc.com

Vicente J. Botet Escriba

tags

participants (4)