Hmm - I would use boost::function instead of declaring a function-pointer object by myself. Regards, Oliver

On 5/2/06, Oliver.Kowalke@qimonda.com wrote:

...

how can I define a function<> object which returns a value of the same type:

This was taken from GotW article 57: http://www.gotw.ca/gotw//057.htm

struct FuncPtr_; typedef FuncPtr_ (*FuncPtr)();

struct FuncPtr_ { FuncPtr_( FuncPtr pp ) : p( pp ) { } operator FuncPtr() { return p; } FuncPtr p; };

Now we can declare, define, and use f() naturally:

FuncPtr_ f() { return f; } // natural return syntax

int main() { FuncPtr p = f(); // natural usage syntax p(); }

HTH,

Michael Fawcett _______________________________________________ Boost-users mailing list Boost-users@lists.boost.org http://lists.boost.org/mailman/listinfo.cgi/boost-users