and I wish to pass the "subarray" as a double** argument and call their function .It's not possible, is it?

you have to create the array of pointers: double trace(double** arr){ double ret=0; for(unsigned i=0; i!=4; ++i){ ret+=arr[i][i]; } return ret; } int main(){ boost::multi_array a(boost::extents[2][2][2][2][2][4] [4]); a[1][1][1][1][1][0][0]=8; a[1][1][1][1][1][3][3]=3; double** sarr=new double*[4]; for(unsigned i=0; i!=4; ++i){ sarr[i]=(&a[1][1][1][1][1][i][0]); } std::cout<< trace( sarr ) <

I am actually able to override their function that takes in a double** data.

Can it work then?

If you can "override" (sic) the function that takes the data, can't you just replace by some multi_array, if there is no pointer arithmetic in the function then that it is easy to do. right? Alfredo