On Thu, Nov 12, 2009 at 1:35 PM, Steven Watanabe <watanabesj@gmail.com>wrote:

AMDG

Lloyd wrote:

...

What is the best way to concatanate an integer to wstring?

for example ===========

std::wstring ws=L"str";

for(int i=0;i<10;++i) { cout<<ws+i; }

The output could be str1 str2 .... str9

ws + boost::lexical_cast<std::wstring>(i)?

In Christ, Steven Watanabe

Or in this particular example: cout << ws << i; although I'm not sure if that's what the OP is really getting at.

Or use stringstreams (which is, I believe, how lexical_cast is implemented). It should look something like this: std::wstringstream oss; std::wstring mystr; std::wstring ws=L"str"; for(int i=0;i<10;++i) { oss << ws << i; } mystr=oss.str(); std::cout << mystr; On 11/12/09, Lloyd <lloyd@cdactvm.in> wrote:

Thanks, it works...

On Fri, 13 Nov 2009 01:05:44 +0530, Steven Watanabe <watanabesj@gmail.com> wrote:

...

AMDG

Lloyd wrote:

...

What is the best way to concatanate an integer to wstring?

for example ===========

std::wstring ws=L"str";

for(int i=0;i<10;++i) { cout<<ws+i; }

The output could be str1 str2 .... str9

ws + boost::lexical_cast<std::wstring>(i)?

In Christ, Steven Watanabe

_______________________________________________ Boost-users mailing list Boost-users@lists.boost.org http://lists.boost.org/mailman/listinfo.cgi/boost-users

______________________________________ Scanned and protected by Email scanner _______________________________________________ Boost-users mailing list Boost-users@lists.boost.org http://lists.boost.org/mailman/listinfo.cgi/boost-users