On Fri, Jun 29, 2007 at 07:05:56AM -0300, Felipe Magno de Almeida wrote:

On 6/29/07, boost@larroy.com wrote:

...

Hello

I'm trying to use multi_index with an ordered_non_unique index. My question is how can I perform a search like with "find(key)" and get all the elements that match that key. Since find only returns one element that match, and there can be several in the container.

Use equal_range. It returns a pair of iterators to begin and end of the equal range.

...

I've tried to iterate "count(key)" times with the iterator returned by find but doesn't seem to work. Is there a way to do this?

Regards

-- Pedro Larroy Tovar, pedro at larroy dot com | http://pedro.larroy.com/ * Las patentes de programación son nocivas para la innovación * http://proinnova.hispalinux.es/

Best regards, -- Felipe Magno de Almeida _______________________________________________ Boost-users mailing list Boost-users@lists.boost.org http://lists.boost.org/mailman/listinfo.cgi/boost-users

Thanks! I didn't noticed that function. -- Pedro Larroy Tovar, pedro at larroy dot com | http://pedro.larroy.com/ * Las patentes de programación son nocivas para la innovación * http://proinnova.hispalinux.es/

Hello Tony, Gottlob Frege writes:

On 6/29/07, Felipe Magno de Almeida wrote:

...

Use equal_range. It returns a pair of iterators to begin and end of the equal range.

Similar question - once I have the equal_range, how do I iterate through them via a different index?

ie ordered_non_unique + ordered_unique

how do I display a list of the items sorted by category, then by item name within each category?

If what you want to do is traverse a range obtained from index #n following the order imposed by index #m, then you can't do that efficiently, sorry. However, the particular case you're posing does not boil down to that, but to something different: ordering elements by lexicographical order according to two keys, here category and ItenName. You can do this by making the category use a composite key on category+itenname. Not sure whether this is what you're after. Does it help? Joaquín M López Muñoz Telefónica, Investigación y Desarrollo