Re: [Boost-users] return type of boost::iostreams::stream<T>::read()
okay, it's within my grasp now. Primarily I get a basic_istream. To facilitate the 'while std::cin' idiom, there is a conversion of basic_istream to void* defined. That seems to hit me in my example. FYI: std::streamsize i = istr.read(buffer,10); is calling the read-function of my DeviceT template parameter, perfect. So I am probably going to use a read + gcount-combination. Thanks again Axel
Hallo Éric,
although it is not an exact fit it will be of value in evaluating my options.
kind regards Axel Strübing
Reading the documentation about boost::iostreams library I could not find the information which return type the boost::iostreams::stream's class is giving me calling read().
From the documentation, a boost::iostreams::stream derives from an std::basic_[i|o]stream, depending on the model of its underlying Device. In your example, the device is a Source, so I guess that the stream derives from std::basic_istream, whose read(char*, streamsize) method returns a basic_istream, not a streamsize.
The library offers the "streamsize read(stream, char*, streamsize)" function template. Using it in your example yould give something like (not tested):
#include
#include #include int main(void){ namespace bio = boost::iostreams; bio::streambio::file_source istr(std::string("in.pdf")); char buffer[10]; std::streamsize i = bio::read(istr,buffer,10); return 0; }
HTH,
Éric Malenfant --------------------------------------------- Two wrongs don't make a right but three rights make a left. --
participants (1)
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Struebing, Axel, le-tex