mmmm... Actually, I would probably create an empty vector and use the list_of in the constructor's body. Another idea I just came up with, is to use an transforming iterator, which iterates over the list_of instance and additionally can be compared with a default constructed iterator instance. Smth like: vector<int> v(my_iterator(list_of(1)(2)), my_iterator()); Regards, Ovanes On Wed, Mar 17, 2010 at 4:16 PM, Ovanes Markarian <om_boost@keywallet.com>wrote:
Actually I tested some of them with gcc and the only solution I came up to resolve ambiguity is:
#include <boost/assign.hpp> #include <vector> #include <iterator> #include <algorithm> #include <iostream>
using namespace std; using namespace boost; using namespace boost::assign;
int main(int argc, char* argv[]) { typedef vector<int> int_vec; int_vec v = list_of(1)(2); int_vec v2(2); v2=list_of(1)(2).to_container(v2);
ostream_iterator<int> oiter(cout, ","); copy(v2.begin(), v2.end(), oiter); }
Hope that helps,
Ovanes
On Wed, Mar 17, 2010 at 1:52 PM, Ovanes Markarian <om_boost@keywallet.com>wrote:
Sorry, it must be to_container() and not to_adapter().
On Wed, Mar 17, 2010 at 1:51 PM, Ovanes Markarian <om_boost@keywallet.com
wrote:
On Wed, Mar 17, 2010 at 1:32 PM, Andrey Torba <andreytorba@gmail.com>wrote:
The code is compilable on msvc but is not on gcc-4.3:
But the problem occurs when i try to initialise std::vector in a class initialization list: class sss { std::vector<int> v; sss() : v(boost::assign::list_of(1)(2)) {} };
What happens if you call: sss() : v(boost::assign::list_of(1)(2).to_adapter()) {}
list_of implements 2 members: implicit conversion opertor to the container type and the to_adapter member. You can cast list_of instance to your vector<int> if that with adapter does not work. Other solution can be:
If you need efficiency, you still can use the vector ctor which reserves the number of items in a vector and than copies the elements from the list.
sss() : v(2) { v = list_of...; }
Regards, Ovanes