Re: [Boost-users] error using lambdas: conversion from 'x' tonon-scalar type 'y'

klaus triendl wrote:

Peter Dimov wrote:

...

Lambda sees that you are invoking operator<< on a MySubStream& and deduces the return type to be MySubStream&; it isn't smart enough to see that you're actually using the operator<< definition for the base class MyStream.

I thought that it would be converted implicitly in the end by the compiler..

There is no implicit conversion from MyStream& to MySubStream&.

Can I make it smart enough?

I showed you one way. Another would be to use ret to force a specific return type: http://www.boost.org/doc/html/lambda/le_in_details.html#lambda.overriding_de...