Re: [Boost-users] Detect specialized template function?

Hi, Daniel. Daniel wrote:

For example, the mere existance of the specialization template <> void S<int>::g() { ... } should trigger special logic in S<int>::f().

Couldn't you explain what "trigger special logic" means? Specializing template for concrete type we trigger special logic, don't we? Best, Andrew -- View this message in context: http://old.nabble.com/Detect-specialized-template-function--tp27363813p27371... Sent from the Boost - Users mailing list archive at Nabble.com.