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There's a terrific article about RVO and copy elision by Dave A at http://cpp-next.com/ If I understand this correctly a decent compiler (say VS2008) will compile this sequence using namespace std; typedef vector< string > V; V get_names( ); V sorted(V names) { sort(names); V ret; swap(ret, names); return ret; } V v = sorted( get_names( ) ); to generate zero copies - the final value of v will be the actual object generated by get_names(). Whereas this code sequence using namespace std; typedef vector< string > V; V get_names( ); V sorted(V names) { sort(names); V ret; swap(ret, names); return ret; } V tmp = get_names( ); V v = sorted( tmp ); Generates exactly one vector copy operation, at the call site of sorted(). Does that sound right? - Rob.