Re: [Boost-users] [Function] Takes functor by value not reference?

Alexander Lamaison wrote:

I may be misunderstanding as the boost::function code is tricky to follow but it seems to me that the function contructor takes the functor it is passed by value rather than by reference.

This requires the functor to be copyable. In my case I'm trying to pass a functor as its abstract supertype which prevents copying. Is it not possible to take the functor my reference, thereby removing the need for copying?

Could you just use a Boost.Ref wrapper? Rather than passing f, you would pass ref(f).