Re: [Boost-users] shared_array const member function

26 Aug 2009


      AMDG

Daya S. Prasad wrote:
...
Can any body please tell me why operator[] is defined in case of
shared_array<T> like this way:
Type & operator[](std::ptrdiff_t) const;
It reports compile time error. Consider the code:
class Widget {
            std::string classId;
public:
            std::string getClassId() const {
                        return classId;
            }
};
int main()
{
            boost::shared_array<Widget> obj(new Widget[10]);
            std::string id = obj[7].getClassId
();                               // Error
}
?
It compiles fine for me.
...
In my opinion operator function should be defined as follows:
const Type & operator[](std::ptrdiff_t) const;
Type & operator[](std::ptrdiff_t) ;
shared_array is defined like a pointer.
  int* const array = new int[5];
  int& i = array[2];
similarly
  const boost::shared_array<int> array(new int[5]);
  int& i = array[2];

In Christ,
Steven Watanabe