Re: [Boost-users] [boost-users][lambda] calling a functor in-place

You need to make the call. The following does NOT seem to work, and I'm not sure why:

for_each (functors.begin(), functors.end(), _1());

Well, that was the experssion I started with. But since it doesn't compile, I thought probably _1 evaluates to (*functor)()...

But the following does work:

void call(function f) { f(); } ... for_each (functors.begin(), functors.end(), call);

Yes, sure, but I'd like to create & call in-place lambda functor - with no complicated bindings etc. - just a trivial one. And I still don't belive it's impossible :-)