Re: [Boost-users] Passing lambda placeholders to functions

23 Jun 2009

      AMDG

Zachary Turner wrote:
...
Thanks.  On a related note, if a lambda placeholder refers to a
structure, is there any way to access its members short of using bind
and making a fake function to perform the access?
For example
struct foo { int x; int y; };
struct bar { int x, int y; };
foo f;
options.add_options()
   ("test", value<bar>()->notifier(
      var(f.x) = _1.x)));
is what I want.  I've tried a variety of different things, most
promising seemed to be
options.add_options()
   ("test", value<bar>()->notifier(
      var(f.x) = bind(&bar::x, _1)));
but this doesn't work either.
It ought to work.  What's the error?

The following works for me:

#include 
#include 
#include <iostream>

struct foo { int x; int y; };
struct bar { int x; int y; };

int main() {
    foo f = { 1, 2 };
    const bar b = { 3, 4 };
    (boost::lambda::var(f.x) = boost::lambda::bind(&bar::x, 
boost::lambda::_1))(b);
    std::cout << f.x << std::endl;
}

In Christ,
Steven Watanabe