Re: [Boost-users] [serialization] Different behaviors between archive and its polymorphic variant

On 08/18/2010 08:33 PM, Robert Ramey wrote:

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So now 'unit' only has a template serialize method, but I still

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int main() { unit u(42);

{ std::cout << "template:" << std::endl; test_oarchive ar(std::cout); ar << BOOST_SERIALIZATION_NVP(u); std::cout << std::endl; }

{ std::cout << "polymorphic:" << std::endl; polymorphic_test_oarchive ar(std::cout); ar << BOOST_SERIALIZATION_NVP(u); std::cout << std::endl; } }

Which outputs:

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template: 42

polymorphic: 42

Code is attached.

what happens when you try:

std::cout << "polymorphic:" << std::endl; polymorphic_oarchive & po = polymorphic_test_oarchive ar(std::cout); po << BOOST_SERIALIZATION_NVP(u); std::cout << std::endl;

This would actually be using the polymorphic interface as it's intended to be used by routing the serialization through the polymorphic interface.

Robert Ramey

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I added:

{ std::cout << "polymorphic with polymorphic_oarchive:" << std::endl; polymorphic_test_oarchive ar(std::cout); boost::archive::polymorphic_oarchive & po = ar; po << BOOST_SERIALIZATION_NVP(u); std::cout << std::endl; }

The output is:

template: 42

polymorphic: 42 polymorphic with polymorphic_oarchive: 42

-- Maxime