Re: [Boost-users] concat integer to wstring

Or use stringstreams (which is, I believe, how lexical_cast is implemented). It should look something like this: std::wstringstream oss; std::wstring mystr; std::wstring ws=L"str"; for(int i=0;i<10;++i) { oss << ws << i; } mystr=oss.str(); std::cout << mystr; On 11/12/09, Lloyd wrote:

Thanks, it works...

On Fri, 13 Nov 2009 01:05:44 +0530, Steven Watanabe wrote:

...

AMDG

Lloyd wrote:

...

What is the best way to concatanate an integer to wstring?

for example ===========

std::wstring ws=L"str";

for(int i=0;i<10;++i) { cout<

The output could be str1 str2 .... str9

ws + boost::lexical_caststd::wstring(i)?

In Christ, Steven Watanabe

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