AMDG Hossein Haeri wrote:
I was looking at the uniform_int<>'s reference page:
http://www.boost.org/doc/libs/1_43_0/doc/html/boost/uniform_int.html
and realised that there is no information whatsoever about what the following overload of its operator () does:
template<typename Engine> result_type operator()(Engine & eng, result_type n) ;
Do I understand it correctly that this generates a number in [min, n] (probably subject to some good conditions)?
No. It generates a number in [0, n). The purpose of this
overload is to allow variate_generator