17 Mar
2008
17 Mar
'08
8:05 p.m.
Hi, I am playing with boost::variant to introduce a more elegant property system into my current project. I was wondering why there are no cast operatorst defined for the variant types, to avoid having to type get<>: boost::variant<double,int,string> v; string s = v; is there a basic reason why this is not possible? Best Daniel