Re: [Boost-users] function template as template parameter

Hi! do you mean this? #include <iostream> template<class T> void function_template(T value) { std::cout << value << std::endl; } struct function_template_wrapper { template static inline void call(T value) { Fct(value); } }; int main(int argc, char* argv[]) { function_template_wrapper::call(10); return 0; } May be you will take a look at boost::function library. Best Regards, Ovanes On Tue, May 29, 2007 17:57, Ares Lagae wrote:

consider the following program:

template <typename T> void function_template(T value) { std::cout << __PRETTY_FUNCTION__ << std::endl; }

struct function_template_wrapper { template <typename T> static void call(T value) { function_template<T>(value); } };

int main(int argc, char* argv[]) { int i; function_template_wrapper::call<int>(i); }

Is it possible to somehow parameterize the struct function_template_wrapper such that I can pass function_template as a parameter?

E.g. function_template_wrapper::call<int>(i); would call function_template<int>(i), and function_template_wrapper::call<int>(i); would call other_function_template<int>(i)

Underlying problem: I want to somehow pass a name of a function template to a class, that will instantiate the function template for a number of types (known at compile time), and store these instantiations in function objects, for later use.

Best regards,

-- Ares Lagae Computer Graphics Research Group, Katholieke Universiteit Leuven http://www.cs.kuleuven.be/~ares/

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