Re: [Boost-users] [bind] and streaming operators for built in types.

On Wed, Aug 26, 2009 at 3:44 PM, Steven Watanabe wrote:

AMDG

Robert Jones wrote:

...

I've asked a similar question before, but I can't seem to locate the mail or recall the answer! In the code below, how can I eliminate f()?

#include "boost/iterator/counting_iterator.hpp" #include "boost/bind.hpp" #include <iostream>

using namespace std; using namespace boost;

ostream & f( ostream & s, int i ) { return s << i; }

int main( ) {  for_each(      make_counting_iterator( 0 ),      make_counting_iterator( 10 ),      bind( & f, ref( cout ), _1 ) ); }

If I write something like

     bind( static_cast< ostream & ( * )( ostream &, int ) >( operator << ), ref( cout ), _1 )

the compiler can't locate operator<<()

Any thoughts, solutions even?

operator<< for int a member function.

template basic_ostream& std::basic_ostream::operator<<(int n);

Look at Phoenix's bind instead of the root bind. Phoenix's bind combines the root bind and lambda's bind all in one. something like this I think would work: // these are all phoenix's version, do not include boost bind, you do not even need bind... int main( ) { for_each( make_counting_iterator( 0 ), make_counting_iterator( 10 ), cout<http://spirit.sourceforge.net/dl_docs/phoenix-2/libs/spirit/phoenix/doc/html...