Oups, sorry but I misunderstood your question. Yes, for such a case like this one: Derived& derived=... boost::reference_wrapper<Base> reference(derived); reference.get().function(); the call to function() will be polymorphic. What is not possible with boost::reference_wrapper is this: boost::reference_wrapper<Derived> derived(...) boost::reference_wrapper<Base> base = derived (and this what I does not understand in the conception of this class) 2008/8/28 Nicolas Vanhoren <nicolas.vanhoren@gmail.com>
No.
By the way, I would be interested to know the rationale for such a strange behavior. If anyone knows something about that...
2008/8/27 Robert Dailey <rcdailey@gmail.com>
Does boost::reference_wrapper provide polymorphic behavior? For
example, if I have a boost::reference_wrapper to a base type, and I assign a derived type to it, will the function calls be polymorphic? _______________________________________________ Boost-users mailing list Boost-users@lists.boost.org http://lists.boost.org/mailman/listinfo.cgi/boost-users