23 Oct
2006
23 Oct
'06
3:34 p.m.
The second, more critical point: The implementation does not seem to be the correct inverse of the original function. Boost's implementation (with above modification) is: -result_type(1) / _lambda * log(eng());
But should actually be: -log(eng()) / _lamda;
The expressions are the same because of operator associativiy. (i.e. x/y*z = (x/y)*z ) I believe you are right about the first point though. cheers Arnaldur