Re: [Boost-users] [function][lambda] Create a boost function to a bind functor

Hi, I can get the following code to compile and it prints 3 2 5 but I don't quite understand why it doesn't print 2 3 5 or how to get it to do so. I thought since it is binding 2 to _1, this would bind it to the a argument. #include #include #include #include <iostream> float fx(float a, float b) { std::cout << a << " " << b << std::endl; return a+b; } int main() { boost::function f = boost::lambda::bind(fx,boost::lambda::_1,2); std::cout << f(3) << std::endl; return 0; } Thanks, Chris On 10/19/06, Arnaldur Gylfason wrote:

a) You want to use _1 instead of _2 b) _1/_2 are in namespace boost::lambda boost::function f = boost::lambda::bind(fx,boost::lambda::_1,2);

It is actually possible to use _2 but then the functor takes to args and ignores the first: boost::function f = boost::lambda::bind(fx,boost::lambda::_2,2); std::cout << f(100,3) << std::endl; // returns 5

cheers

Arnaldur