Sorry,
I ment enable_if< is_decimal_type<T> >::type. The ::type will be expanded to
either void or a derivable type.
Ovanes.
-----Original Message-----
From: Ovanes Markarian [mailto:om_boost@keywallet.com]
Sent: Mittwoch, 7. März 2007 17:43
To: boost-users@lists.boost.org
Subject: Re: [Boost-users] [enable_if] using enable_if
toextendstd::numeric_limits?
Hi!
I think you need to derive your class from enable_if< is_decimal_type<T> >.
If your compiler supports SFINAE and is_decimal_type<T>::value is false_
template will be derived from void which is not legal...
Best Regards,
Ovanes
-----Original Message-----
From: james.jones@firstinvestors.com [mailto:james.jones@firstinvestors.com]
Sent: Mittwoch, 7. März 2007 17:21
To: boost-users@lists.boost.org
Subject: [Boost-users] [enable_if] using enable_if to
extendstd::numeric_limits?
Suppose I have a set of templates that have a common interface (each is a
model of the same concept, to use that lingo). I'd like to extend
std::numeric_limits to support this concept. I'm trying to find a way to use
enable_if to do this, but I don't see how. Is this possible? Is there some
other trick to doing this?
Example with code (not real code):
template< class U, class V >
class model1;
tempalte< class U, class V >
class model2;
template< class U >
is_decimal_type { static const bool value = false; };
template< class U, class V >
is_decimal_type < model1