Re: [Boost-users] commandline args

24 Aug 2009

      Hi Harmut,

Thank you for the answers. However, I am still having some trouble and
i figure it out following the documentation on the list operator.

I am trying to produce an output like below:
Options not recognized:
  "dd"
  "-e"
  "rrty"

However,
bk::generate(ostream_iterator<char>(cout), "Command line options not
recognized:\n" << ("  \"" << ba::string % "\"" << bk::eol) << bk::eol,
vsUnrecog);

does not do the trick and

bk::generate(ostream_iterator<char>(cout), "Command line options not
recognized:\n" << ("  \"" % ba::string % "\"" << bk::eol) << bk::eol,
vsUnrecog);

fails with "..\Dependency\boost\boost/spirit/home/karma/string/lit.hpp(108)
: error C2664: 'boost::mpl::assertion_failed' : cannot convert
parameter 1 from 'boost::mpl::failed ************(__thiscall
boost::spirit::karma::any_string::generate::string_not_usable_without_attribute::*
***********)(void)' to 'boost::mpl::assert<false>::type'" (which I
guess is not the way it should fail? Shouldnt there be a nice
assertion message or is this it? no experience with it really)

What am I missing here?

Best and thanks,
Dee

On Mon, Aug 24, 2009 at 11:21 AM, Hartmut
Kaiser wrote:
...
...
Really? Thank you for that tip! That brings me to a few questions (I
was just testing it and couldn't get it to work quickly). What is the
sink? I think i can just replace that with cout, right? Actually, no,
that gets me an compile error
"boost/spirit/home/karma/detail/output_iterator.hpp(295) : error
C2675: unary '++' : 'std::ostream' does not define this operator or a
conversion to a type acceptable to the predefined operator".
ok, what i got now is:
#include 
namespace bk  = boost::spirit::karma;
namespace ba  = boost::spirit::ascii;
vector<string> vsUnrecog =
collect_unrecognized(parsed.options,po::exclude_positional);
bk::generate(cout, "Option \"" << ba::string % '\" not recognized' <<
bk::eol, vsUnrecog);
Where do those sinks come from and how do I make a simple sink that
writes to stdout, just like cout does?
I used 'sink' as a placeholder for any output iterator, so in your case the easiest is to construct an ostream_iterator<char>(cout).
...
By the way, doen't your code both use ";" and newline (eol) as
delimiters?
';' is used as the delimiter in between the elements of the vector (string % ';': in Spirit operator% is used as the shortcut for 'list'), and eol is used as the closing newline.
Regards Hartmut
...
Best,
Dee
On Mon, Aug 24, 2009 at 10:42 AM, OvermindDL1
wrote:
...
On Sun, Aug 23, 2009 at 8:20 PM, Diederick C.
Niehorster wrote:
...
...
The same way that you would stream any normal vector:
vector<string> &files = vm["file"].as< vector<string> >();
vector<string>::const_iterator iter = files.begin();
cout << "Files selected: ";
for(;iter!=files.end();++iter)
{
   cout << *iter << ";";
}
cout << "\n";
...
Consequently, if you have Boost trunk installed, then you could do
this as well since it does support streaming vectors:
#include 
using namespace boost::spirit::karma;
using namespace boost::spirit::ascii;
generate(cout, "Files selected: " << (*char_)%';' << eol,
vm["file"].as< vector<string> >());
Or you could simply do:
#include 
cout << "Files selected: ";
BOOST_FOREACH(string& sFile, vm["file"].as< vector<string> >())
           cout << sFile.c_str() << endl;
That is assuming you wanted an endl at the end of each name, a usual
delimiter is something like ';' or so, so this instead:
cout << "Files selected: ";
BOOST_FOREACH(string& sFile, vm["file"].as< vector<string> >())
          cout << sFile.c_str() << ";";
cout << "\n";
Although the karma version that Hartmut posted is still the fastest
way to do it (in terms of execution speed):
generate(sink,
  "Files selected: " << string % ';' << eol,
  vm["file"].as< vector<string> >());
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Re: [Boost-users] commandline args

Diederick C. Niehorster