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24 Jun
2008
24 Jun
'08
1:43 p.m.
This pattern/idiom is well-established: struct A { virtual A* clone () = 0; }; struct B : public A { virtual B* clone (); }; But the above does not work when the pointers A* and B* are replaced by shared_ptr<A> and shared_ptr<B>: struct A { virtual shared_ptr<A> clone () = 0; }; struct B : public A { virtual shared_ptr<B> clone (); }; Is there a workaround? Another way to solve the same problem? Thanks! -John