Hello,
Should the following code sample work? It is the simplest reproduction
case I
could come up with:
#include
#include
#include
#include
using namespace std;
using namespace boost;
using namespace boost::lambda;
int main(void)
{
void * myResource = malloc(5);
shared_ptr<void> mySharedResource(myResource, bind(free, _1));
}
I get a compile error using g++ 4.0.1 on Mac OS X:
/Documents/boost_1_34_0/boost/detail/sp_counted_impl.hpp: In member
function
'void* boost::detail::sp_counted_impl_pd::get_deleter(const
std::type_info&) [with P = void*, D =
boost::lambda::lambda_functor >, boost::tuples::tuple >,
boost::tuples::null_type, boost::tuples::null_type,
boost::tuples::null_type,
boost::tuples::null_type, boost::tuples::null_type,
boost::tuples::null_type,
boost::tuples::null_type, boost::tuples::null_type> > >]':
test.cpp:13: instantiated from here
/Documents/boost_1_34_0/boost/detail/sp_counted_impl.hpp:150: error: no
match
for ternary 'operator?:' in '(+ ti)->std::type_info::operator==(((const
std::type_info&)((const std::type_info*)(&
_ZTIN5boost6lambda14lambda_functorINS0_19lambda_functor_baseINS0_6action
ILi2ENS0
_15function_actionILi2EvEEEENS_6tuples5tupleIRFvPvEKNS1_INS0_11placehold
erILi1EE
EEENS7_9null_typeESG_SG_SG_SG_SG_SG_SG_EEEEEE))))
? boost::lambda::operator&(const boost::lambda::lambda_functor<T>&)
[with Arg =
boost::lambda::lambda_functor_base >, boost::tuples::tuple >,
boost::tuples::null_type, boost::tuples::null_type,
boost::tuples::null_type,
boost::tuples::null_type, boost::tuples::null_type,
boost::tuples::null_type,
boost::tuples::null_type, boost::tuples::null_type> >]() : 0'
Of course, just using "free" instead of bind(free, _1) works, but my
real case
is more complicated and this appears to be a general conflict between
lambda::bind and shared_ptr.
Thanks,
Scott French
