I realize one thing more. My code refers to cT and tT template arguments:
Template
void function(const cT& o)
....
double array[n];
if (n==2)
binomial code depends on cT,tT (array[0] array[1])
else if (n==3)
trinomial code depends on cT,tT (array[0] array[1] array[2])
else
....
The "do_n_specific_code" cannot therefore be just a function...
I'll take a wrapping class that includes a public static function with same
signature,
And the class can be partially specialized.
-----Original Message-----
From: boost-users-bounces@lists.boost.org
[mailto:boost-users-bounces@lists.boost.org] On Behalf Of Steven Watanabe
Sent: 18 March 2008 18:47
To: boost-users@lists.boost.org
Subject: Re: [Boost-users] template int argument
AMDG
Hicham Mouline wrote:
hi,
I have a template function
{
....
double array[n];
if (n==2)
binomial code
else if (n==3)
trinomial code (array[0] array[1] array[2])
else
....
compiler tries to compile the "trinomial code" code even when the template
is instantiated with n=2,
and that gives warnings because of array[2]
Is there a way to make the compiler ignore the non-binomial code ?
rds,
You'll have to split it out into a separate function and use template
specialization/overload resolution.
template<int n>
void do_n_specific_code(double (&array)[n]);
template
void f() {
double array[n];
do_n_specific_code(array);
}
In Christ,
Steven Watanabe
_______________________________________________
Boost-users mailing list
Boost-users@lists.boost.org
http://lists.boost.org/mailman/listinfo.cgi/boost-users
