Re: [Boost-users] Testing whether result_of<F(U)> is a valid expression

2013/2/8 oswin krause

Hi,

Is it possible to evaluate, whether a certain argument type given to a functor will lead to a valid expression with the result_of template?

i am trying to achieve the following, maybe there is a better way to do it:

template Container< typename boost::result_of::type > transform( Container<T> c, F f, std::disable_if >::type* dummy = 0 ){ //slow default implementation Container<T> res(c.size()); std::transform(c.begin(),c.**end(),res.begin(),f): return res; }

//blocked implmentation of transform template Container< typename boost::result_of::type > transform( Container<T>, F functor, std::enable_if >::type* dummy = 0 ){ //functor supports fast implementation Container<T> res(c.size()); std::transform(c.blocks().**begin(),c.blocks().end(),res.**blocks().begin(),functor):

return res; }

the question is, how valid_expression could be implemented and right now the only mechanism which get's close to what i want would be checking result_of is valid.

Hmm... I have implemented `has_call` some time ago, your code may be rewritten as has_call. Interested?