Hi there,
I found that the behavior of replace_all_regex is weird while specifing format flag as format_literal.
For example, I would like to replace %f and %g in a source with some
text respectively. The code is
string source = "#f = %f \r\n #g = %g \r\n";
string text1("");
string text2("""name""");
replace_regex(source, boost::regex("%f"), text1, boost::regex_constants::format_literal);
replace_regex(source, boost::regex("%g"), text2, boost::regex_constants::format_literal);
The result is fine. However, I would like to use replace_all_regex instead. i.e.
replace_all_regex( source, boost::regex("(%f|%g)"), string("(?1 loofon@56.com)(?2 ""name"""), boost::regex_constants::format_literal);
However, because of format_literal, what I get is
#f = (?1 loofon@56.com)(?2 "name"")
#g = (?1 loofon@56.com)(?2 "name"")
rather than
#f = loofon@56.com
#g = "name""
In my case, I need to handle a heap of patterns and using replace_all_regex is convenient. Any way to use both
replace_all_regex and format_literal without going into the trouble mentioned above?
Thanks in advance.
