The memcpy should copy from randomBytes into seed.  (Assuming I
haven't forgotten the signature of memcpy.)

Seems, like I forgot the signature... Another way to transfer the bytes would be:

union bytes2seed
{
   uint64_t seed_;
   char      bytes_[sizeof(uint64_t)];
}; 

bytes2seed converter;

Now one can pass &converter.bytes_[0] to CryptGenRandom. This does not require an additional memcpy call.


Ovanes.