[Boost-users] How to convert a vector of base classes to template based code?

10 Jul 2008

      Hi,

The following program uses virtual functions. Essentially I need to go
through all the pairs in 'v'.

Since I have already know what are in v at compile time. I would like
to convert the dynamic polymorphism to template. Therefore, the
runtime would be better. I think this should be done with the help of
boost::mpl. But I'm not sure how to do it. Would you please help me?

Thanks,
Peng

#include <iostream>
#include <vector>
#include <boost/shared_ptr.hpp>

struct shape {
 virtual void show_me() const = 0;
 virtual ~shape() { }
};

struct square : public shape {
 void show_me() const {
   std::cout << "square";
 }
};

struct circle : public shape {
 void show_me() const {
   std::cout << "circle";
 }
};

struct triangle : public shape {
 void show_me() const {
   std::cout << "triangle";
 }
};

int main() {
 std::vector<boost::shared_ptr<shape> > v;
 {
   boost::shared_ptr<shape> s(new square);
   v.push_back(s);
 }
 {
   boost::shared_ptr<shape> s(new circle);
   v.push_back(s);
 }
 {
   boost::shared_ptr<shape> s(new square);
   v.push_back(s);
 }
 {
   boost::shared_ptr<shape> s(new triangle);
   v.push_back(s);
 }

 for(std::vector<boost::shared_ptr<shape> >::const_iterator it =
v.begin(); it != v.end(); ++ it) {
   for(std::vector<boost::shared_ptr<shape> >::const_iterator it2 =
it + 1; it2 != v.end(); ++ it2) {
     (*it)->show_me();
     std::cout << " vs. ";
     (*it2)->show_me();
     std::cout << std::endl;
   }
 }
}

[Boost-users] How to convert a vector of base classes to template based code?

Peng Yu