Re: [Boost-users] [boost-users][lambda] calling a functor in-place

Igor R [boost.lists@gmail.com], le 17 juillet 2008 10:09:

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typedef boost::function functor; std::vector<functor> functors; ... using namespace boost::lambda; std::for_each( functors.begin(), functors.end(), bind(&functor::operator(),_1));

Oh, I see... So the explicit bind is unavoidable :(.

As shown here: http://www.boost.org/doc/libs/1_35_0/doc/html/lambda/le_in_details.html#lamb..., the bind() is unavoidable, but it does not have to be that explicit. This should work: std::for_each(functors.begin(), functors.end(), bind(_1)); Note that Lambda may be unable to deduce the return type for some functors. See http://www.boost.org/doc/libs/1_35_0/doc/html/lambda/le_in_details.html#lamb... for more information. Éric Malenfant --------------------------------------------- Sometimes I think the surest sign that intelligent life exists elsewhere in the universe is that none of it has tried to contact us. - Calvin