Re: [Boost-users] [Function] Overloaded functor as a boost::function

On Sun, 14 Feb 2010 01:11:21 +0000, Alexander Lamaison wrote:

I'm trying to pass a function with an overloaded operator() to a function expecting a boost::function parameter. This fails to compile as it appears to pick the wrong overload.

My bad. I was using a subclass of the functor and name hiding came into play. A 'using' declaration fixed this. Thanks Alex