[Boost-users] boost::serialization - prevent object creation when loading a pointer

11 Dec 2007

      I realise that what I am doing is no doubt an unconventional usage of 
boost::serialization, but I wonder if any one has done a similar thing 
before.

I wish to serialize a derived class through a baseclass pointer, but on 
deserilize I do not want the object to be created (I do not want memory 
allocated) - as the object will have all ready been created.

An example, hopefully showing what I mean, is given at the end. The 
program will output something like,

    construct A, _m = 155640808
    serialise A, _m = 155640808
    construct A, _m = 155649400
    serialise A, _m = 155649808

But essentially I want the program to output something lke,

    construct A, _m = 155640808
    serialise A, _m = 155640808
    construct A, _m = 155649400
    serialise A, _m = 155649400

i.e. the second lot of construct A/serialise A will have the same 
address for _m.

The reason why I need this behaviour, is that only a sub-set of the 
derived class will be seriliazed, with the other parts of the class 
intialised differently depending on the session, and the initialisation 
of the class is always done _before_ deserialisation.

Is there anyway to get this behaviour from the boost::serialization library?

Many thanks,
Darryl

Example
-------

#include <fstream>
#include <boost/archive/text_oarchive.hpp>
#include <boost/archive/text_iarchive.hpp>
#include <boost/serialization/export.hpp>

using namespace std;

struct base {
    virtual ~base() {}
    template<class Archive>
    void serialize(Archive& ar, const unsigned int version) {}
};

struct derived : public base {
    derived() : base(), _value(0) {}

    template<class Archive>
    void serialize(Archive& ar, const unsigned int version) {
        boost::serialization::void_cast_register<derived, base>();
        ar & _value;
    }

    int _value;
};

BOOST_CLASS_EXPORT(derived);

struct A {
    A() {
        _m = new derived;
        cout << "construct A, _m = " << (unsigned long)_m << endl;
    }

    template<class Archive>
    void serialize(Archive& ar, const unsigned int version) {
        // On deserialize this will create a new object, but I do not 
want it to,
        // rather I would like it to deserialize into the all ready created
        // object.
        ar & _m;
        cout << "serialise A, _m = " << (unsigned long)_m << endl;
    }

    base* _m;
};

void save(const A& a, const char* filename) {
    std::ofstream ofs(filename);
    boost::archive::text_oarchive oa(ofs);
    oa << a;
}

void load(A& a, const char* filename) {
    std::ifstream ifs(filename);
    boost::archive::text_iarchive ia(ifs);
    ia >> a;
}

int main(int argc, char* argv[]) {
    A a;
    save(a, "archive.txt");
    A new_a;
    load(new_a, "archive.txt");
    return 0;
}

[Boost-users] boost::serialization - prevent object creation when loading a pointer

Darryl Lawson