Re: [Boost-users] Boost.Function and Boost.Bind

AMDG Yang Zhang wrote:

...

bind(twice, protect(bind(show, 0)))

Thanks, this works. Would anybody be able to explain what just happened? According to:

bind(twice, bind(show, 0))() is evaluated as twice(show(0)) You want: twice(bind(show, 0)) The protect prevents show from being evaluated immediately by Boost.Bind. In Christ, Steven Watanabe