Re: [Boost-users] [Regex] Is it possible to match any "linebreak"

John Maddock wrote:

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Is there a way to have a regex like [[:digit:]]{3}([^\n]+)\n? have \n match any line breaking character? (The processed files might have Unix or DOS line endings.)

Use \R, see:

http://www.boost.org/doc/libs/1_49_0/libs/regex/doc/html/boost_regex/syntax/...

HTH, John.

Thank you John. Somehow I must have overlooked \R in the docs. However, I still have one issue with \R. In the following code everything works fine if I use r2. If r1 the matches' captures do contain the newlines. In short: ([^\\R+]) does not seem to capture all non-linebreak characters. Should it? Or is this just a misunderstanding on my part? #include #include #include BOOST_AUTO_TEST_CASE(test_boost_regexp) { // works fine boost::regex r1("\\d\\d\\d([^\\R]+)\\R*"); // boost::regex r2("\\d\\d\\d([^\\r\\n]+)\\R*"); boost::smatch what; std::string input("123hallo welt\n\r"); BOOST_CHECK(boost::regex_match(input, what, r1)); // ok with r1, but fails with r2: the capture does contain the newline BOOST_CHECK_EQUAL(what[1], "hallo welt"); input="123hallo welt\n"; BOOST_CHECK(boost::regex_match(input, what, r1)); BOOST_CHECK_EQUAL(what[1], "hallo welt"); input="123hallo welt\r"; BOOST_CHECK(boost::regex_match(input, what, r1)); BOOST_CHECK_EQUAL(what[1], "hallo welt"); } Best regards Christoph