Re: [Boost-Users] Using function_traits

I'm trying to use the function traits to extract the return type of a template parameter, but it's not compiling.

Any ideas what's wrong here?

Yes, function_traits takes a function type as parameter, *not* a function pointer type: function_traits // OK function_traits // not OK. So throw in a remove_pointer into your code and everything should be well:

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template<typename Proc> class CacheValue { typedef boost::remove_pointer<Proc>::type np_type; typedef boost::function_traits::R ReturnType; template<typename Arg1> ReturnType operator () ( Arg1 arg1 ) { /* do something */ } }; CacheValue aValue;

-------- end simplified code ------

John Maddock http://ourworld.compuserve.com/homepages/john_maddock/index.htm