--- At Mon, 2 Sep 2002 18:48:08 +0100, Alex Henderson wrote:
Hi,
I'd like boost::bind to use overloaded member functions, but get an internal compiler error. Does bind support overload resolution, or is my compiler at fault? (...or more likely the code!)
This seems like a simple ambiguity problem more than overload resolution, although overload resolution seems to play a part. All bind() gets is the address of a function. If there are more than one function with the same name, then AFAIK, there's no syntax for saying which function to use. The solution that I have used is to not overload, or to have a function that is not overloaded that calls the overloaded function, or to have a free function that calls the overloaded function. If there is a syntax for this situation, I would love to know what it is.
system = C++Builder 5 (patched), Win2k, boost_1_28_0 example (simplified) code below
Thanks, Alex //-------------------------------------------------------------------- -------
#include <string> #include <vector> #include <iostream> #include <boost/bind.hpp>
//-------------------------------------------------------------------- -------
struct part { std::string name; int id; part(std::string name, int id) : name(name), id(id) {} bool is(int test) { return id == test; } // bool is(std::string test) { return name == test; } // uncomment for error }; //-------------------------------------------------------------------- -------
int main() { int x = 6; // swap comments here for error // std::string x("handle"); // swap comments here for error
std::vector<part> parts; part a("top", 3); parts.push_back(a); part b("spout", 6); parts.push_back(b); part c("handle", 9); parts.push_back(c);
std::vector<part>::iterator it = std::find_if(parts.begin(), parts.end(), boost::bind(&part::is, _1, x));
std::cout << it->name << std::endl;
return 0; }
...Duane -- "If tyranny and oppression come to this land, it will be in the guise of fighting a foreign enemy." - James Madison