[Boost-users] lexical_cast and default params

1 Dec 2009

      Running into something very strange with boost::lexical_cast in 1.39.

This code works, but notice the f().  If I attempt to get rid of it and 
call boost::lexical_cast directly in the constructor for test I get this 
error:

1>d:\dev_workspace\experimental\scratch\scratch\main.cpp(16) : error 
C2783: 'Target boost::lexical_cast(const Source &)' : could not deduce 
template argument for 'Target'
1>        d:\boostvs39\include\boost\lexical_cast.hpp(1164) : see 
declaration of 'boost::lexical_cast'

This is hard for me to understand since I've given the target type as a 
template parameter....and the f() version works just fine.  It even 
works if I make it inline as the lexical_cast function is.

Any ideas?

#include 
#include <string>
#include <iostream>

template < typename R, typename T >
R f(T const& x)
{
  return boost::lexical_cast<R>(x);
}

template < typename T >
struct test
{
  test(std::string const& x = fstd::string(T()))
    : test_string(x) {}

  std::string test_string;
};

int main()
{
  test<int> t;

  std::cout << t.test_string;
  std::cout << boost::lexical_caststd::string(int());

  std::cin.get();
}

[Boost-users] lexical_cast and default params

Noah Roberts