Re: [Boost-users] [variant][mpl] silly mistake in make_variant_over usage?

On Fri, Aug 28, 2015 at 9:47 PM, Agustín K-ballo Bergé wrote:

On 8/28/2015 10:35 PM, Nat Goodspeed wrote:

...

(Is there a simpler way to obtain a variant of the result types of passed functions? I was hoping I could just write: boost::variant< std::result_of<Fns>::type... >.)

So probably this would to:

typedef boost::variant< typename std::result_of::type...> >::type return_t;

Thank you very much! Indeed, this works: typedef boost::variant< typename std::result_of::type... > return_t; So my silly mistake was omitting the parentheses. :-)