Re: [Boost-users] [serialization] Different behaviors between archive and its polymorphic variant

18 Aug 2010

...
...
So now 'unit' only has a template serialize method, but I still
...
int main()
{
  unit u(42);
{
    std::cout << "template:" << std::endl;
    test_oarchive ar(std::cout);
    ar << BOOST_SERIALIZATION_NVP(u);
    std::cout << std::endl;
  }
{
    std::cout << "polymorphic:" << std::endl;
    polymorphic_test_oarchive ar(std::cout);
    ar << BOOST_SERIALIZATION_NVP(u);
    std::cout << std::endl;
  }
}
Which outputs:
...
template:
42

polymorphic:
42
Code is attached.
what happens when you try:

std::cout << "polymorphic:" << std::endl;
polymorphic_oarchive & po = polymorphic_test_oarchive ar(std::cout);
po  << BOOST_SERIALIZATION_NVP(u);
std::cout << std::endl;

This would actually be using the polymorphic interface as it's
intended to be used by routing the serialization through the polymorphic
interface.

Robert Ramey