Re: [Boost-users] Fusion. transform_view example

John Christopher wrote:

Hello, The example at the bottom of: http://spirit.sourceforge.net/dl_more/fusion_v2/libs/fusion/doc/html/fusion/... does not compile; I am using MinGw 3.4.2.

[snip]

More specifically it is the line std::cout << transform << std::endl;

Works fine for me. See attached.

that seems to create the problem. I was also wondering why operator() of square return int and not T.

Yes, it should be T. Noted. Thanks for spotting that. It's corrected in the cpp file I just sent. Regards, -- Joel de Guzman http://www.boost-consulting.com http://spirit.sf.net /*============================================================================= Copyright (c) 2001-2006 Joel de Guzman Use, modification and distribution is subject to the Boost Software License, Version 1.0. (See accompanying file LICENSE_1_0.txt or copy at http://www.boost.org/LICENSE_1_0.txt) ==============================================================================*/ #include <iostream> #include #include struct square { template <typename T> struct result { typedef T type; }; template <typename T> T operator()(T x) const { return x * x; } }; int main() { using namespace boost::fusion; typedef vector vector_type; vector_type vec(2, 5, 3.3); transform_view transform(vec, square()); std::cout << transform << std::endl; return 0; }