Re: [Boost-users] [Phoenix] expression does not name a type

Hi Gordon, Thank you for your reply. Incredibly, somehow, i forget to combine the boost::phoenix namespace. I think i did it mentally, but forget to compile. :-P Regards, Júlio. 2011/9/22 Gordon Woodhull

On Sep 22, 2011, at 2:12 PM, Júlio Hoffimann wrote:

Dear all,

I can't understand why this test case is not compiling:

#include #include #include #include <iostream> using namespace boost::phoenix::placeholders; expression::argument<1>::type X;

try

typename boost::phoenix::expression::argument<1>::type X;

or something equivalent

int main ( int argc, char *argv[] ){ boost::function f; f = if_else( X == 0, X, X*2 ); std::cout << f(0) << f(12) << std::endl; return 0;} // ---------- end of function main ----------

The error message says 'expression' does not name a type. I've tried to explicitly play with boost::phoenix namespaces, but doesn't work.

HTH, Gordon

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