Ok, I apologize I misunderstood the suggestion I made the function as non static member, but kept the input argument. If I make myfunc to take void, then it works. I would like to know if there any way to use static member functions with the for_each sematic and shared_ptr thank you, Vlad On Tue, 24 Feb 2009 21:04 -0500, boost-users@lists.boost.org wrote:
Hi, thank you for such a quick reply
I have tried the member function, getting different type of error now class B; struct A : public enable_shared_from_this<A> { void myfunc(const A* in) {} }; ------------------------------------------------ sharedptr.cpp C:\usr\local\MSVS9.0\VC\INCLUDE\algorithm(29) : error C2064: term does not evalu ate to a function taking 1 arguments class does not define an 'operator()' or a user defined conversion opera tor to a pointer-to-function or reference-to-function that takes appropriate num ber of arguments sharedptr.cpp(38) : see reference to function template instantiation '_F n1 std::for_each<std::_Vector_iterator<_Ty,_Alloc>,boost::_mfi::mf1<R,T,A1>>(_In It,_InIt,_Fn1)' being compiled with [ _Fn1=boost::_mfi::mf1<void,A,const A *>, _Ty=B::tBptr, _Alloc=std::allocator<B::tBptr>, R=void, T=A, A1=const A *, _InIt=std::_Vector_iterator<B::tBptr,std::allocator<B::tBptr>> ]
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Also, is there a way to get the for_each and shared_ptr to work with static member functions? I tried std::ptr_fun but that one also has a problem that does not even try to call the shared_ptr::get_pointer
I also tried to enabled BOOST_MEM_FN_ENABLE_CDECL (which is what I use for the project) -- that did not help. I tried even just having myfunc take const shared_ptr<A> or shared_ptr<B> -- that did not work either.
thank you again for your help, Vlad
On Tue, 24 Feb 2009 17:42 -0800, "Steven Watanabe" <watanabesj@gmail.com> wrote:
AMDG
V S P wrote:
struct A: public enable_shared_from_this<A> { static void myfunc(const A* in); };
for_each (v.begin(),v.end(), boost::mem_fn(&A::myfunc));
A::myfunc is a static member function, so mem_fn doesn't work. If you declare it as a non-static member void myfunc() const; it works.
In Christ, Steven Watanabe
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