Richard Vock
I don't really know wether this is a Boost.Thread related question or a general c++ related, but since I couldn't decide I will disturb you first ;)
Maybe you have the patience to look at this minimalistic framework (I stripped almost all functionality):
This compiles well and running it gives me the expected:
# starting # This is A # This is B # shutting down
The problem is, that I want to run the kernels as threads. Have (again) a look at the highlighted lines (27-29):
If I replace 27 by 28+29 I (expectedly) get a compile error since Kernel is abstract. However if I make it non-abstract by implementing the operator() in it, it is this function (namely Kernel::operator()) which get's called instead of TestKernel::operator().
Yes. This is because boost::thread copies the objects into the new thread. You can't copy an object through a reference to abstract base since you cannot create an instance of the base class. If you make the base non-abstract then it slices, and calls the base operator(). You can use boost::ref to fix this: boost::thread t(boost::ref(*m_kernel[i])); Of course you have to ensure that the m_kernel objects outlive the threads if you do this. Anthony -- Author of C++ Concurrency in Action | http://www.manning.com/williams just::thread C++0x thread library | http://www.stdthread.co.uk Just Software Solutions Ltd | http://www.justsoftwaresolutions.co.uk 15 Carrallack Mews, St Just, Cornwall, TR19 7UL, UK. Company No. 5478976