2014/1/10 Sebastian Pfützner <s.pfuetzner@onlinehome.de>
On 09.01.2014 17:43, Krzysztof Czainski wrote:
That said, here's a hack for you: right after the definition of struct S insert this code:
class It;
namespace boost { namespace detail { template <> struct operator_brackets_result<It,S,S&> { typedef S& type; }; }}
That works in the example. In my real code, /It/ is a template and I don't know how to specialize operator_brackets_result for each instantiation.
It should be possible to write a partial specialization of operator_brackets_result<> for the whole template It. For example: template < class T > class It; namespace boost { namespace detail { template < class T > struct operator_brackets_result<It<T>,T,T&> { typedef T& type; }; }} Regards Kris