Re: [Boost-users] [iterator] error while accessing member of result of brackets-operator

2014/1/10 Sebastian Pfützner

On 09.01.2014 17:43, Krzysztof Czainski wrote:

...

That said, here's a hack for you: right after the definition of struct S insert this code:

class It;

namespace boost { namespace detail { template <> struct operator_brackets_result { typedef S& type; }; }}

That works in the example. In my real code, /It/ is a template and I don't know how to specialize operator_brackets_result for each instantiation.

It should be possible to write a partial specialization of operator_brackets_result<> for the whole template It. For example: template < class T > class It; namespace boost { namespace detail { template < class T > struct operator_brackets_result { typedef T& type; }; }} Regards Kris