On 26.08.2011 20:21, Ovanes Markarian wrote:

On Fri, Aug 26, 2011 at 2:30 PM, Martin B. <0xCDCDCDCD@gmx.at

<mailto:0xCDCDCDCD@gmx.at>> wrote:

   Say I have a range R and I want to construct a new container from
   the range R. Will I always have to repeat the expression yielding
   the range, or is there a shorter way?

   Example:

       std::vector<int> numbers(
         boost::irange(7, 42).begin(),
         boost::irange(7, 42).end()
       );

What about that:

...

integer_range<int> ir=irange(7,42);
vector<int> numbers(ir.begin(), ir.end());

For this to work I need the exact type of the range, which can be quite annoying as far as I could tell. (Plus, I *don't want* to care what type of the range is.)

Really, if I had C++11/auto, I wouldn't mind so much, i.e.

   auto xr = get_some_range(...);
   vector<int> numbers(xr.begin(), xr.end());

but I don't have an `auto` capable compiler, so spelling out the range type for this is really crappy.